求[sin²xcos2xdx
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求定积分∫xcos2xdx∫xcos2xdx因为不太懂求定积分∫xcos2xdx∫xcos2xdx因为不太懂求定积分∫xcos2xdx∫xcos2xdx因为不太懂原式=1/2∫xcos2xd2x=1/
求不定积分∫xcos2xdx求过程答案!谢谢!求不定积分∫xcos2xdx求过程答案!谢谢!求不定积分∫xcos2xdx求过程答案!谢谢!∫xcos2xdx=(1/2)∫xcos2xd2x=(1/2)
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