{y=2x-1,2x+3y+z=8,3x+2z=-4解下列方程组

试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z 已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX.. 已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值 已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值 (4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? 分式加减的几道题目求速度1 .(x+y)²/（x-z)(y-z) - (y+z)²/（x-z)(y-z) = 2.2x+3y/x-y+2y/y-x-3y/x-y= x+Y+Z=1 X+3Y+7Z=-1 X+5Y+8Z=2x+Y+Z=1X+3Y+7Z=-1X+5Y+8Z=2 (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian {x+y+z=1 x-2y+3z=5 2x-3y-3z=-8 {x+2y+z=8{2x-y-z=-3{3x+y-2z=-1 {x+2y+z=8,2x-y-z=-3,3x+y-2z=-1 x+y+z=-1 4x-2y+3z=5 y-z=8-2x 2x+3y+z=8 4x-y-z=10 x+2y-z=1 {x+y+z=1 {x+3y+7z=-1 {x+5y+8z=2 X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z x+y+z=6 x+2y+3z=14 y+1=z {x+y+z=1;x+3y+7z=-1;z+5y+8z=-2