y=cos(x/2-π/6)-sin(x/2-π/6)的单调递增区间是什么

y=(sin x + COS x)^2 y=2cos x (sin x+cos x) sin(x+y)sin(x-y)=k,求cos^2x-cos^2y 证明COS（X+Y）COS（X-Y）=COS^2X-SIN^2Y 证明cos(x+y)cos(x-y)= cos^2(x)-sin^2(y) 1.y=sin(-X+π/6)2.y=cos(-2X+π/3) 化简y=sin^2(x)+2sin(x)cos(x)+3cos^2(x) 6-4x-x^2=5/|sin(y/x)cos(y/x)|的解 求导：y=x-sin(x/2)cos(x/2). 已知sinx=3/5,x∈(π/2,π),求【sin(x+y)+sin(x-y)】/【cos（x+y）+cos（x-y）】的值 y =(cos^2) x - sin (3^x),求y' 函数Y=sin(2x+π/3)cos(x-π/6)-cos(2x+π/3)sin(x-π/6)的图像的一条对称轴方程是多少 Sin x-sin y=2/3 cos x-cos y=1/2 求cos(x-y) 函数y=cos^2(3x+π/6)-sin^2(3x+π/6)化简 y=sin(2x-π/6)-3cos(2x-π/6)的值域 求y=sin(2x+π/3)+cos(2x-π/6)的单调区间 函数y=sin(π/2+x)cos(π/6-x)的最大值为 y=sin(π/2+x)+cos(π/6-x)的最大值是不是相加是相乘