解分式1-（1/1-x）-（x²-2x+1/x²-1）怎么解?1-（1/1-x）-（x²-2x+1/x²-1）怎么解啊!

解分式1-（1/1-x）-（x²-2x+1/x²-1）怎么解?1-（1/1-x）-（x²-2x+1/x²-1）怎么解啊!
解分式1-（1/1-x）-（x²-2x+1/x²-1）怎么解?
1-（1/1-x）-（x²-2x+1/x²-1）怎么解啊!

解分式1-（1/1-x）-（x²-2x+1/x²-1）怎么解?1-（1/1-x）-（x²-2x+1/x²-1）怎么解啊!
1-（1/1-x）-（x²-2x+1/x²-1）
=(x²-1)/(x²-1)+(x+1)/(x²-1)-(x-1)²/(x²-1)
=(x²-1+x+1-x²-1+2x)/(x²-1)
=(3x-1)/(x²-1);
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解
原式=(x²-1)/(x²-1)+(x+1)/(x²-1)-(x²-2x+1)/(x²-1)
=(x²-1+x+1-x²+2x-1)/(x²-1)
=(3x-1)/(x²-1)

1- 1/(1-x）-（x²-2x+1）/（x²-1）
=(1-x-1)/(1-x) - (x-1)²/[(x+1)(x-1)]
=-x/(1-x) - (x-1)/(x+1)
=x/(x-1) - (x-1)/(x+1)
=[x(x+1)-(x-1)²]/[(x+1)(x-1)]
=(x²+x-x²+2x-1)/[(x+1)(x-1)]
=(3x-1)/[(x+1)(x-1)]