x^2+y^2-4x+10y+16=0

来源:学生作业帮助网 编辑:六六作业网 时间:2024/05/21 05:04:19
x^2+y^2-4x+10y+16=0x^2+y^2-4x+10y+16=0x^2+y^2-4x+10y+16=0x^2+y^2-4x+10y+16=0(x-2)^2+(y+5)^2-13=0(x-2

x^2+y^2-4x+10y+16=0
x^2+y^2-4x+10y+16=0

x^2+y^2-4x+10y+16=0
x^2+y^2-4x+10y+16=0
(x-2)^2+(y+5)^2-13=0
(x-2)^2+(y+5)^2=13=2^2+3^2=(-2)^2+(-3)^2
if x-2 =2 or -2 ,y+5=3 or -3
x=5 or -1,y=-3 or -7
if x-2=3 or -3y+5=2 or -2
x=4 0r 0 y=-2 or -8

x²+y²-4x+10y+16=0
(x²-4x)+(y²+10y+16)=0
x(x-4)+(y+8)(y+2)=0

方程化为 [X-2]^2+[Y+5]^2=13
^13以内的平方数只有1.4.9.并且4+9=13
所以【X-2]^2=4.[Y+5]^2=9 X1=4.X2=0.Y1=-2.Y2=-8
或者[X-2]^2=9.[Y+5]^2=4.X3=5.X4=-1.Y3=-7.Y4=-3