计算:[(x-y)^2+3(x^2-(1/3)y^2)]/2x

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计算:[(x-y)^2+3(x^2-(1/3)y^2)]/2x计算:[(x-y)^2+3(x^2-(1/3)y^2)]/2x计算:[(x-y)^2+3(x^2-(1/3)y^2)]/2x解原式=[(x

计算:[(x-y)^2+3(x^2-(1/3)y^2)]/2x
计算:[(x-y)^2+3(x^2-(1/3)y^2)]/2x

计算:[(x-y)^2+3(x^2-(1/3)y^2)]/2x

原式
=[(x²-2xy+y²)+3x²-y²]/2x
=(4x²-2xy)/2x
=2x-y