-x^2+x(x>0) y= x^2+x(x≥0） 判断函数的奇偶性,

x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 求y=(x^2)+2x(x≥0) y=-x+2x(x Y=X^2X (X>0) 求导Y=X^2X (X>0) 求d(Y)/d(X) y=x^2-2x (x≥0) -x^2-2x(x 因式分解x(x+y)(x-y)-x(x+y)^2 y=x^2-2x（x y=x^2+2x(x 3^x+2x=y,x 变量x,y满足x-2y=0,x 若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7 mathematica软件,已知y[x],Y=f1(x),X(x)=f2(x),如何plot Y[X]?y[x_] := x + 9.81/2*x*xk=1X[x] = x - k*y'[x]/(1 + (y'[x])^2)^0.5Y[x] = y[x] + k/(1 + (y'[x])^2)^0.5Plot[{y[x],Y[X],},{x,0,2}] y=1-x^2 x>=0 ,y=sin|x|/x x 先化简,再求值 [2/3x - 2/x+y（x+y/3x -x-y）]*x/x-y,其中5x+3y=0 先化简,再求值:[3x-2/x+y(x+y/3x-x-y)]/(x-y/x),其中5x+3y=0 y=1/x^2(x>0) y=(1-x)/(1+x) y=(e^x-e^-x)/2 若x+y=1,x不等于0则x+(2xy+y^2)/x/(x+y)/x= 已知x>0,Y>0,如何证x^2/y+y^2/x>=x+y x*x+2x+y*y-4y+5=0 x= y=