f(x)=log1/2^(-x^2+2x+3),求值域~

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f(x)=log1/2^(-x^2+2x+3),求值域~f(x)=log1/2^(-x^2+2x+3),求值域~f(x)=log1/2^(-x^2+2x+3),求值域~f(x)=log‹1

f(x)=log1/2^(-x^2+2x+3),求值域~
f(x)=log1/2^(-x^2+2x+3),求值域~

f(x)=log1/2^(-x^2+2x+3),求值域~
f(x)=log‹1/2›(-x²+2x+3),求值域
设f(x)=log‹1/2›u,u=-x²+2x+3=-(x²-2x)+3=-[(x-1)²-1]+3=-(x-1)²+4≦4,故0