(1)(x+3)(x-2)-(x-3)² (2)(x+2)² -(x-1)(x+1)=?(3)(x+2y)(x+3y)+(x-2y)² +(x-3y)² (4)(x+3)(x-3)(x² -9)=?(5)[(a-3分之1)² +(a+3分之1)² ](2a² +9分之2)=?
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(1)(x+3)(x-2)-(x-3)²(2)(x+2)²-(x-1)(x+1)=?(3)(x+2y)(x+3y)+(x-2y)²+(x-3y)²(4)(x+3
(1)(x+3)(x-2)-(x-3)² (2)(x+2)² -(x-1)(x+1)=?(3)(x+2y)(x+3y)+(x-2y)² +(x-3y)² (4)(x+3)(x-3)(x² -9)=?(5)[(a-3分之1)² +(a+3分之1)² ](2a² +9分之2)=?
(1)(x+3)(x-2)-(x-3)²
(2)(x+2)² -(x-1)(x+1)=?
(3)(x+2y)(x+3y)+(x-2y)² +(x-3y)²
(4)(x+3)(x-3)(x² -9)=?
(5)[(a-3分之1)² +(a+3分之1)² ](2a² +9分之2)=?
(1)(x+3)(x-2)-(x-3)² (2)(x+2)² -(x-1)(x+1)=?(3)(x+2y)(x+3y)+(x-2y)² +(x-3y)² (4)(x+3)(x-3)(x² -9)=?(5)[(a-3分之1)² +(a+3分之1)² ](2a² +9分之2)=?
(1)(x+3)(x-2)-(x-3)² =x²+x-6-(x²-6x+9)=7x-15
(2)(x+2)² -(x-1)(x+1)=x²+4x+4-(x²-1)=4x+5
(3)(x+2y)(x+3y)+(x-2y)² +(x-3y)² =x²+5xy+6y²+x²-6xy+9y²=2x²-xy+15y²
(4)(x+3)(x-3)(x² -9)=(x²-9)²=x^4-18x²+81
(5)[(a-3分之1)² +(a+3分之1)² ](2a² +9分之2)=(a²-2/3a+1/9+a²+2/3a+1/9)(2a² +2/9)
=(2a²+2/9)²=4a^4+8a²/9+4/81
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