（1+√3i）³=-8

（1+√3i）³=-8
（1+√3i）³=-8

（1+√3i）³=-8
1+√3i=2(cos60°+isin60°),
由狄莫佛定理,(1+√3i)^3=2^3*(cos180°+isin180°)=-8.
解2：（1+√3i)^3
=1+3√3i+3(√3i)^2+(√3i)^3
=1+3√3i-9-3√3i
=-8.