解分式方程:(x^2-8)/(x^2-10)=(x^2-3x+2)/(x^2-3x)

来源:学生作业帮助网 编辑:六六作业网 时间:2024/05/05 19:19:29
解分式方程:(x^2-8)/(x^2-10)=(x^2-3x+2)/(x^2-3x)解分式方程:(x^2-8)/(x^2-10)=(x^2-3x+2)/(x^2-3x)解分式方程:(x^2-8)/(x

解分式方程:(x^2-8)/(x^2-10)=(x^2-3x+2)/(x^2-3x)
解分式方程:(x^2-8)/(x^2-10)=(x^2-3x+2)/(x^2-3x)

解分式方程:(x^2-8)/(x^2-10)=(x^2-3x+2)/(x^2-3x)
因为:(x^2-8)/(x^2-10)=(x^2-3x+2)/(x^2-3x)
所以:[(x^2-8)-(x^2-10)]/(x^2-10)=[(x^2-3x+2)-(x^2-3x)]/(x^2-3x)
2/(x^2-10)=2/(x^2-3x)
1/(x^2-10)=1/(x^2-3x)
(x^2-10)=(x^2-3x)
3x=10
x=10/3