(1/3)^[log(1/2)^(x^2-3x+1)]

来源:学生作业帮助网 编辑:六六作业网 时间:2024/05/09 00:31:11
(1/3)^[log(1/2)^(x^2-3x+1)](1/3)^[log(1/2)^(x^2-3x+1)](1/3)^[log(1/2)^(x^2-3x+1)]由原式可得(1/3)^[log(1/2

(1/3)^[log(1/2)^(x^2-3x+1)]
(1/3)^[log(1/2)^(x^2-3x+1)]

(1/3)^[log(1/2)^(x^2-3x+1)]
由原式可得(1/3)^[log(1/2)^(x^2-3x+1)]<(1/3)^0
所以log(1/2)^(x^2-3x+1)>0
又因为底数是1/2,所以
0解得0或者 (3+√5)< x<3