main() { int a,x,y; a=5; a+=3; printf("a=%d \n",a); x=2; y=3; x*=y+8; printf("x=%d \n",x); x=8; x%=3;printf("x=%d \n",x);}运行结果如下：a=8x=22x=2在计算机中a+=3,x*=y+8,x%=3,是怎样运算的,结果是如何计算出来的

main() { int a,x,y; a=5; a+=3; printf("a=%d \n",a); x=2; y=3; x*=y+8; printf("x=%d \n",x); x=8; x%=3;printf("x=%d \n",x);}运行结果如下：a=8x=22x=2在计算机中a+=3,x*=y+8,x%=3,是怎样运算的,结果是如何计算出来的
main() { int a,x,y; a=5; a+=3; printf("a=%d \n",a); x=2; y=3; x*=y+8; printf("x=%d \n",x); x=8; x%=
3;printf("x=%d \n",x);
}
运行结果如下：
a=8
x=22
x=2
在计算机中a+=3,x*=y+8,x%=3,是怎样运算的,结果是如何计算出来的

main() { int a,x,y; a=5; a+=3; printf("a=%d \n",a); x=2; y=3; x*=y+8; printf("x=%d \n",x); x=8; x%=3;printf("x=%d \n",x);}运行结果如下：a=8x=22x=2在计算机中a+=3,x*=y+8,x%=3,是怎样运算的,结果是如何计算出来的
a+=3就是
a=a+3
=5+3
=8
x*=y+8就是
x=x*(y+8)
=2*(3+8)
=22
x%=3就是
x=x%3
=8%3
=2