(x-3)²+2(x-3)=0

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(x-3)²+2(x-3)=0(x-3)²+2(x-3)=0(x-3)²+2(x-3)=0(x-3)²+2(x-3)=0(x-3)[(x-3)+2]=0/这一步

(x-3)²+2(x-3)=0
(x-3)²+2(x-3)=0

(x-3)²+2(x-3)=0
(x-3)²+2(x-3)=0
(x-3)[(x-3)+2]=0 /这一步是提取公因式
(x-3)(x-1)=0
x=3或x=1