1/1x4 + 1/4x7 + 1/7x10 +…+ 1/91x94=?
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1/1x4+1/4x7+1/7x10+…+1/91x94=?1/1x4+1/4x7+1/7x10+…+1/91x94=?1/1x4+1/4x7+1/7x10+…+1/91x94=?1/1x4=(1-1
1/1x4 + 1/4x7 + 1/7x10 +…+ 1/91x94=?
1/1x4 + 1/4x7 + 1/7x10 +…+ 1/91x94=?
1/1x4 + 1/4x7 + 1/7x10 +…+ 1/91x94=?
1/1x4=(1-1/4)/3,1/4x7 =(1/4-1/7)/3,1/7x10 =(1/7-1/10)/3,.1/91x94=(1/91-1/94)/3
所以原式=(1/3)*(1-1/4+1/4-1/7+1/7-1/10+...+1/91-1/94)=(1/3)*(1-1/94)=(1/3)*(93/94)=31/94
100x( 3/1x4 + 3/4x7 +3/7x10 +.3/97x100)=?注：1x4、4x7、7x10等均为分母的大小
x8+x7+x6 +x5+x4+x3+x2+x+1因式分解
x8+x7+x6+x5+x4+x3+x2+x+1因式分解
x1-x2+x3=1x2-x3+x4=21若x1,x2,x3,x4,x5满足方程组 x3-x4+x5=3x4-x5+x1=4x5-x1+x2=5求x2 x3 x4的值2已知 x1+x4+x6+x7=39 x2+x4+x5+x7=49 x3+x5+x6+x7=41 x4+x7=13 x5+x7=14 x6+x7=9 x1+x2+x3+x4+x5+x6+x7=9求x7的值若x1,x2,x3,x4,x5满足方程组 x1-x
1/1x4+1/4x7+…+1/97x100
lim[1/(1x4)+1/(4x7)+1/(7x10)+...+1/(3n-2)x(3n+1)]=_____
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1/1X4+1/4X7+1/7X10+...+1/100X103=
1/1x4+1/4x7+1/7x10+……+1/97x100SOS!SOS!
1/(1x4)+1/(4x7)+1/(7x10)+...+1/(91x94)
1/1X4+1/4X7+1/7X10+.+1/2002X2005=?有规律的
1/1x4+1/4x7+1/7x10+……+1/2005x2008
1X4/1+4X7/1+7X10/1+…+2005X2008/1=?
1/1x4 +1/4x7+1/7x10+.+1/100x103 急用啊
小学分数题：1/1x4+1/4x7+1/7x10+.+1/97x100