解方程组:3(x-3)+10(2/3+y)=13,22(x-3)+5(2/3+y)=27

来源:学生作业帮助网 编辑:六六作业网 时间:2024/06/10 10:48:30
解方程组:3(x-3)+10(2/3+y)=13,22(x-3)+5(2/3+y)=27解方程组:3(x-3)+10(2/3+y)=13,22(x-3)+5(2/3+y)=27解方程组:3(x-3)+

解方程组:3(x-3)+10(2/3+y)=13,22(x-3)+5(2/3+y)=27
解方程组:3(x-3)+10(2/3+y)=13,22(x-3)+5(2/3+y)=27

解方程组:3(x-3)+10(2/3+y)=13,22(x-3)+5(2/3+y)=27
3(x-3)+10(2/3+y)=13 (1)
22(x-3)+5(2/3+y)=27 (2)
(2)*2-(1)得
44(x-3)+10(2/3+y)-3(x-3)-10(2/3+y)=54-13
41(x-3)=41
x-3=1
x=4
将x=4代入(1)得
3(4-3)+10(2/3+y)=13
3+10(2/3+y)=13
10(2/3+y)=10
2/3+y=1
y=1/3

x=4,y=1/3

9x+30y=46 1
66x+15y=269 2
132x+30y=538 3
3式-1式