2x(x+2y)+2(x+1)^2-(2x)^2-4x 其中x=25分之1 y=25
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2x(x+2y)+2(x+1)^2-(2x)^2-4x其中x=25分之1y=252x(x+2y)+2(x+1)^2-(2x)^2-4x其中x=25分之1y=252x(x+2y)+2(x+1)^2-(2
2x(x+2y)+2(x+1)^2-(2x)^2-4x 其中x=25分之1 y=25
2x(x+2y)+2(x+1)^2-(2x)^2-4x 其中x=25分之1 y=25
2x(x+2y)+2(x+1)^2-(2x)^2-4x 其中x=25分之1 y=25
2x(x+2y)+2(x+1)^2-(2x)^2-4x
=2x²+4xy+2x²+4x+2-4x²-4x
=4xy+2
把x=1/25 y=25代人上式得:
4×5×1/25+2
=6
....等于6
最后就剩下4XY+2,带进去正好XY没了..
化简后将x、y代入,即求出结果。这样的题目也求助,实在是手太懒。
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