5/2(x+y)=1200,10/3(x-y)=1200这个方程组怎么解?
来源：学生作业帮助网 编辑：六六作业网 时间：2024/05/17 02:21:26
5/2(x+y)=1200,10/3(x-y)=1200这个方程组怎么解?5/2(x+y)=1200,10/3(x-y)=1200这个方程组怎么解?5/2(x+y)=1200,10/3(x-y)=12
5/2(x+y)=1200,10/3(x-y)=1200这个方程组怎么解?
5/2(x+y)=1200,10/3(x-y)=1200这个方程组怎么解?
5/2(x+y)=1200,10/3(x-y)=1200这个方程组怎么解?
5/2(x+y)=1200,10/3(x-y)=1200;x+y=1200(2/5)=480 为（1）,x-y=1200(3/10)=360,为（2）；(1)+(2):2x=840,x=420;y=60.
5/2(x+y)=10/3(x-y)
求出x=2y
再代到之前的算式中求解就可以了
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
x-y/7 - x+y/10 =1/2 2(x-y)-5(x+y)=3修改、、、、（x-y)/7-(x+y)/10=1/2 2(x-y)-5(x+y)=3
5(x+y)-2x=0 3x-10(x+y)=2
{2X=5(X+Y) 3X-10(X+Y)=2
{2X=5(X+Y)3X-10(X+Y)=2怎么解?
{2x=5(x y) 3x-10(x y)=2
3(2X+Y)+(2(2x-Y)=6 (8X+4y)-(10X-5Y)=2
已知x,y满足约束条件 2x+5y>=10 2x-3y>=-6 2x+y
已知x,y满足约束条件{2x+5y>=10,2x-3y>=-6,2x+y
{ x-y/7-x+y/10=1/2 {2(x-y)+5(x+y)=3
{ x-y/7-x+y/10=1/2 {2(x-y)+5(x+y)=3
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
已知实数x,y满足2x+5y>=10;2x-3y>-6;2x+y
10/x+y+3/x-y=-5 15/x+y-2/x-y=-1（用换元法解此方程组）
解分式方程：10/(x+y)+3/(x-y)=-5,15/(x+y)-2/(x-y)=-1
3/(X-Y)+10/(X+Y)=-5 2/(X-Y)-15/(X+Y)=1 解分式方程组
｛x/60+y/80=10,x/60+y/40=15、｛2x/3+3y/4=1/5,5x/6-5y/2=2、｛5/2(x+y）=1200,10/3（x+y）=1200｛4x+5y=98,5y-4x=2、｛x/3+y/4=54/60,y/4+x/5=42/60怎么解?{40-y=x-4 40-y=y-x