∫ln﹙x²+1﹚dx

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∫ln﹙x²+1﹚dx∫ln﹙x²+1﹚dx∫ln﹙x²+1﹚dx∫ln﹙x²+1﹚dx=xln(x²+1)-∫[2x²/﹙x²+

∫ln﹙x²+1﹚dx
∫ln﹙x²+1﹚dx

∫ln﹙x²+1﹚dx
∫ln﹙x²+1﹚dx
=xln(x²+1)-∫[2x²/﹙x²+1﹚]dx
=xln(x²+1)-2∫[1-1/﹙x²+1﹚]dx
=xln(x²+1)-2x+2arctanx+ c