{3x+2y=6,5x-2y=64(用加减消元法做)

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{3x+2y=6,5x-2y=64(用加减消元法做){3x+2y=6,5x-2y=64(用加减消元法做){3x+2y=6,5x-2y=64(用加减消元法做)相加得(3x+2y)+(5x-2y)=6+6

{3x+2y=6,5x-2y=64(用加减消元法做)
{3x+2y=6,5x-2y=64(用加减消元法做)

{3x+2y=6,5x-2y=64(用加减消元法做)
相加得 (3x+2y)+(5x-2y)=6+64
8x=70
x=35/4
代入3x+2y=6
得 105/4+2y=6
y=-81/8
∴﹛x=35/4,y=-81/8时原方程组的解