3(x-1)³y-(1-x)³z
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3(x-1)³y-(1-x)³z3(x-1)³y-(1-x)³z3(x-1)³y-(1-x)³z3(x-1)³y-(1-x)&su
3(x-1)³y-(1-x)³z
3(x-1)³y-(1-x)³z
3(x-1)³y-(1-x)³z
3(x-1)³y-(1-x)³z
=3(x-1)³y+(x-1)³z
=(x-1)³(3y+z)
3(x-1)³(y+z)