函数y=sin(3x+π/3)cos(x-π/6)+cos(3x+π/3)cos(x+π/3)的图像的一条对称轴的方程是?

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函数y=sin(3x+π/3)cos(x-π/6)+cos(3x+π/3)cos(x+π/3)的图像的一条对称轴的方程是?函数y=sin(3x+π/3)cos(x-π/6)+cos(3x+π/3)co

函数y=sin(3x+π/3)cos(x-π/6)+cos(3x+π/3)cos(x+π/3)的图像的一条对称轴的方程是?
函数y=sin(3x+π/3)cos(x-π/6)+cos(3x+π/3)cos(x+π/3)的图像的一条对称轴的方程是?

函数y=sin(3x+π/3)cos(x-π/6)+cos(3x+π/3)cos(x+π/3)的图像的一条对称轴的方程是?
cos(x+π/3)=sin(π/2-x-π/3)=sin(π/6-x)=-sin(x-π/6)
y=sin(3x+π/3)cos(x-π/6)+cos(3x+π/3)cos(x+π/3)
=sin(3x+π/3)cos(x-π/6)-cos(3x+π/3)sin(x-π/6)
=sin(3x+π/3-x+π/6)
=sin(2x+π/2)
=cos(-2x)
=cos2x,
它的一条对称轴方程式x=0.

y=sin(3x+π/3)cos(x-π/6)+cos(3x+π/3)cos(x+π/3)
y=sin(3x+π/3)cos(x-π/6)-cos(3x+π/3)sin(x-π/6)
y=sin(3x+π/3-x+π/6)
y=sin(2x+π/2)
对称轴为 x=kπ/2不对!!! 答案是 x=π/4!!!明显答案错误 对称轴为 x=kπ/2 k取任...

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y=sin(3x+π/3)cos(x-π/6)+cos(3x+π/3)cos(x+π/3)
y=sin(3x+π/3)cos(x-π/6)-cos(3x+π/3)sin(x-π/6)
y=sin(3x+π/3-x+π/6)
y=sin(2x+π/2)
对称轴为 x=kπ/2

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y=sin(3x+π/3)cos(x-π/6)+cos(3x+π/3)cos(x+π/3)
=sin(3x+π/3)cos(x-π/6)+cos(3x+π/3)cos(x+π/3)
=sin(3x+π/3)cos(x-π/6)-cos(3x+π/3)sin(x-π/6)
=sin(3x+π/3-(x-π/6))=sin(2x+π/2)
sin(2x+π/2)=0 2x+π/2=kπ=π x=π/4

函数y=sin(3x+π/3)cos(x-π/6)+cos(3x+π/3)cos(x+π/3)的图像的一条对称轴的方程是?
y=sin(3x+π/3)cos(x-π/6)+cos(3x+π/3)cos(x+π/2-π/6)
=sin(3x+π/3)cos(x-π/6)-cos(3x+π/3)sin(x-π/6)=sin[(3x+π/3)-(x-π/6)]=sin(2x+π/2)=c...

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函数y=sin(3x+π/3)cos(x-π/6)+cos(3x+π/3)cos(x+π/3)的图像的一条对称轴的方程是?
y=sin(3x+π/3)cos(x-π/6)+cos(3x+π/3)cos(x+π/2-π/6)
=sin(3x+π/3)cos(x-π/6)-cos(3x+π/3)sin(x-π/6)=sin[(3x+π/3)-(x-π/6)]=sin(2x+π/2)=cos2x
令cos2x=1,即得2x=0,故x=0就是其一条对称轴的方程。其全部对称轴为:x=kπ/2,k∈Z.
注意!!点(π/4,0)是对称中心,x=π/4不是对称轴!全部对称中心为:(π/4+kπ/2,0).
在你的选项中可以选D,即x=-π/2作对称轴(此时k=-1).
你用五点作图法画个图就可立判谁对谁错!我发现你这个“爱是衣服”不爱动脑子,你判断
对错的唯一标准就是你书上的“答案”,你有没有想过:书上的答案若是错的呢?

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