sin^4(a/2)-cos^(4a/2)=

sin^4+sin^2cos^2+cos^2a= 化简：sin^4a+cos^2a-sin^2a-cos^4a sin^4a-cos^4a=sin^2a-cos^2a 证明sin^4a-cos^4a=sin^2a-cos^2a 用 cos a表示 sin^4 a-sin^2 a+cos^2 a tan a =3求4sin a-2cos a/5cos+3sin a 化简 1-sin^4a-cos^4a/cos^2a-cos^4a 化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)== sin(a-π)+5cos(2π-a)+4cos(π+a)/cos(π-a)-sin(-a) 求 (cos a)^4+(sin a)^2*(sin a)^2+(sin a)^2=? cosA+cos^2A=1,sin^2A+sin^4A+sin^8A (1-sin^6a-cos^6a)/(sin^2a-sin^4a) 由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证：1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a) sin^4a-cos^4a=sin^2-cos^2a 求证1/sin^2a+3/cos^2a>=4+2根号下31/sin²a +3/cos²a=(sin²a+cos²a)/sin²a +3(sin²a+cos²a)/cos²a=1+cos²a/sin²a+3+3sin²a/cos²a=4+cos²a/sin²a+3sin²a/cos²a≥4+2√[(cos (1-sin^4a-cos^4)/(sin^2a-sin^4a) 化简 =1-（sin^6a+cos^6a） ------（1）=1-（sin^a+cos^a)(sin^4 a-sin^acos6a+cos^4 a) --------（2）由（1）怎么能到（2）呢=1-（sin^6a+cos^6a）=1-（sin^2a+cos^2a)(sin^4 a-sin^2acos^2a+cos^4a) cos (a+4pai)cos ^2(a+pai)sin^2(a+3pai)/ sin(a-4pai)sin(5pai+a)cos^2(-a-pai)