tan(a+b)=5,tan(a-b)=3求tan2a,tan2b的值?

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tan(a+b)=5,tan(a-b)=3求tan2a,tan2b的值?tan(a+b)=5,tan(a-b)=3求tan2a,tan2b的值?tan(a+b)=5,tan(a-b)=3求tan2a,

tan(a+b)=5,tan(a-b)=3求tan2a,tan2b的值?
tan(a+b)=5,tan(a-b)=3求tan2a,tan2b的值?

tan(a+b)=5,tan(a-b)=3求tan2a,tan2b的值?
tan(2a)=tan(a-b+a+b)
=(tan(a-b)+tan(a+b))/(1-tan(a-b)tan(a+b))
=(3+5)/(1-3*5)
=-4/7
tan(2b)=tan((a+b)-(a-b))
=(tan(a+b)-tan(a-b))/(1+tan(a-b)tan(a+b))
=(3-5)/(1+3*5)
=-1/8