求：limx→1 [(x²-1)/(x-1)]e^(1/x-1)

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求：limx→1[(x²-1)/(x-1)]e^(1/x-1)求：limx→1[(x²-1)/(x-1)]e^(1/x-1)求：limx→1[(x²-1)/(x-1)]e

求：limx→1 [(x²-1)/(x-1)]e^(1/x-1)
求：limx→1 [(x²-1)/(x-1)]e^(1/x-1)

求：limx→1 [(x²-1)/(x-1)]e^(1/x-1)
limx→1 [(x²-1)/(x-1)]e^(1/x-1)
=limx→1 [(x+1)]e^(1/x-1)
=2

用咯必达法则就可以了