已知a2-5a+1=0,求a4+a2+1/a2=
来源：学生作业帮助网 编辑：六六作业网 时间：2024/05/11 23:28:56
已知a2-5a+1=0,求a4+a2+1/a2=已知a2-5a+1=0,求a4+a2+1/a2=已知a2-5a+1=0,求a4+a2+1/a2=a2+1=5a平方a4+2a2+1=25a2两边减去a2
已知a2-5a+1=0,求a4+a2+1/a2=
已知a2-5a+1=0,求a4+a2+1/a2=
已知a2-5a+1=0,求a4+a2+1/a2=
a2+1=5a
平方
a4+2a2+1=25a2
两边减去a2
a4+a2+1=24a2
所以a4+a2+1/a2=24
(1+5)×(10-6)=24
(10-1-5)×6=24
(a+b)2=22
a2+b2+2ab=4
a2+b2=4-2ab=4+2=6
所以b/a+a/b
=(a2+b2)/ab
=6/(-1)
=-6