∫[cosx+1/(1+x²)-1/√(1-x²)]dx=

来源：学生作业帮助网编辑：六六作业网时间：2024/05/30 19:17:04

∫[cosx+1/(1+x²)-1/√(1-x²)]dx=∫[cosx+1/(1+x²)-1/√(1-x²)]dx=∫[cosx+1/(1+x²)-1

∫[cosx+1/(1+x²)-1/√(1-x²)]dx=
∫[cosx+1/(1+x²)-1/√(1-x²)]dx=

∫[cosx+1/(1+x²)-1/√(1-x²)]dx=
原积分=sinx+arctanx-arcsinx+C