若(3x+2y)^2+/2x+3y+5/=0,则x,y分别等于多少?

化简:5(x-y)+2(x+y)-3(x-y) 已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y) (2x-3y)-(5x-y) (2X-3y)-(5x-y) (2x-5y)(3x+y) 因式分解(x-2y)(x-3y)+(x-4y)(x-5y)+（x-3y)(x-5y)+(x-2y)(x-4y) (2x+y)²+(x+3y)(x-3y)-x(5x+8y)因式分解 [2(x-y)^5-8(x-y)^2(x+y)+6y(x-y)^2]÷2(x-y)^2[2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2]÷2(x-y)^2 x(x-y)2-(y-x)3 若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值 [2/3x-2/x+y(x+y/3x-x-y)]/x-y/x 化简：{2/3x-2/(x+y)[(x+y)/3x-x-y]}/(x+y)/x 计算2/3x-2/x+y(x+y/3x-x-y)/x-y/x [(x+2y)(x-2y)-(2x-y)^2+(3x-y))2x-5y)]/(-x)我急用 化简3x-2/(x+y)[(x+y)/3x-x-y]÷(x-y)/x [(x+2y)(x-2y)-(2x-y)²+(3x-y(2x-5y)]/(-x)的解答 若x-y/x+y=5,求x-y/2x+2y+5x+5y/3x-3y的值 若3x-5y=0,则x+y/x=（）,x-y/y=（）,2x-3y/2x+3y=( )