y=(5x-1)/(4x+2) x∈[-3,1]且x≠-1/2,求值域

若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7 化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1 求y=(5x-1)/(4x+2) (x 求值域 1.y=-x+x+2,x∈(-1,2] 2.y=8/x-4x+5 3.y=x-2√x求值域1.y=-x+x+2,x∈(-1,2]2.y=8/x-4x+53.y=x-2√x+3 xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 {x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0 （x+2y)(x-2y)(x^2-4y^2),其中x=2,y=-1（x+5)^2-(x-5)^2-5(2x+1)(2x-1)+x·(2x)^2,其中x=-1 化简求值{(x=2y)(5x-2y)-(3x+2y)(3x-2y)]/4x,其中x=2,y=-1 3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2 x*x+2x+y*y-4y+5=0 x= y= {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11 3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27 {6(x-y)-7(x+y)=21 {2(x-y)-5(x+y)=-1 (x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5) 1.y=x²-4x+6,x∈[1,5]2.y=2x-√x-1根号在 x-1 这里 3x-2y=1 4x-5y (x-y)/4+(x+y)/5=1/4 (x+y)/9-(x-y)/3=//2(x-y)/4+(x+y)/5=1/4(x+y)/9-(x-y)/3=//2