3(x-1)+2(x+1)=-6 x-1/4=1+x+1/3 2x-2/3(x-3)=1/3[x-3(x-1)+2(x+1)=-6x-1/4=1+x+1/32x-2/3(x-3)=1/3[x-1/2(3x+1)]

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3(x-1)+2(x+1)=-6x-1/4=1+x+1/32x-2/3(x-3)=1/3[x-3(x-1)+2(x+1)=-6x-1/4=1+x+1/32x-2/3(x-3)=1/3[x-1/2(3x

3(x-1)+2(x+1)=-6 x-1/4=1+x+1/3 2x-2/3(x-3)=1/3[x-3(x-1)+2(x+1)=-6x-1/4=1+x+1/32x-2/3(x-3)=1/3[x-1/2(3x+1)]
3(x-1)+2(x+1)=-6 x-1/4=1+x+1/3 2x-2/3(x-3)=1/3[x-
3(x-1)+2(x+1)=-6
x-1/4=1+x+1/3
2x-2/3(x-3)=1/3[x-1/2(3x+1)]

3(x-1)+2(x+1)=-6 x-1/4=1+x+1/3 2x-2/3(x-3)=1/3[x-3(x-1)+2(x+1)=-6x-1/4=1+x+1/32x-2/3(x-3)=1/3[x-1/2(3x+1)]
 

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