n2-n+1=0,则n3-n2-n+5=

来源：学生作业帮助网编辑：六六作业网时间：2024/05/09 14:41:32

n2-n+1=0,则n3-n2-n+5=n2-n+1=0,则n3-n2-n+5=n2-n+1=0,则n3-n2-n+5=已知n²-n+1=0则n²-n=-1n=(1±√5)/2n&

n2-n+1=0,则n3-n2-n+5=
n2-n+1=0,则n3-n2-n+5=

n2-n+1=0,则n3-n2-n+5=
已知
n²-n+1=0
则
n²-n=-1
n=(1±√5)/2
n³-n²-n+5
=n(n²-n)-n+5
=-2n+5
=4±√5