设z属于C,满足z+1/z属于R,z-(1/4)是纯虚数,求z

设z属于C,满足z+1/z属于R,z-(1/4)是纯虚数,求z
设z属于C,满足z+1/z属于R,z-(1/4)是纯虚数,求z

设z属于C,满足z+1/z属于R,z-(1/4)是纯虚数,求z
设z=a+bi,z-(1/4)是纯虚数可得 a+bi-1/4=(a-1/4)+bi是纯虚数,a-1/4=0,a=1/4.
z+1/z属于R,可列：a+bi+[1/(a+bi)],后一项上下同乘(a-bi)得：
a+bi+(a-bi)/(a^2-b^2),因为它属于R实数,所以虚部为0即：
解不下去了.你表达式哪写错了?