∫(X-2)/(x∧2-4x-5)dx怎么求?

∫x/(x^4+2(x^2)+5)dx ∫x/(x^2-4x-5)dx ∫ x/√(x^2+4x+5)dx ∫x/((x^2)+4x+5)dx ∫X√(2-5X)dx ∫x/（x^2+5）dx ∫（x^2+1/x^4)dx ∫dx/根号(4x-x^2) ∫1/(x^4-x^2)dx ∫x/(4+9x^2)dx ∫(x^3-x^2+x+1)/(x^2+1) dx∫(x+4)/(x^2-x-2) dx 这个怎恶魔算∫cos x / ( 1 + (sinx)^2 ) dx = ∫x^3 / ( 1 + x^4 ) dx = ∫(sec x)^3 * tan x dx = ∫x^2 * e^(-2x) dx = ∫x * cos 2x dx = ∫(cos 2x)^2 dx = ∫(13x - 6) / ( x (x-2)(x+3) )dx = ∫(x^2 + 2x - 2) / ((x-2)(x+1)) dx = ∫（x∧4/x∧2+1）dx ∫x-1/x∧2-5dx求解 求解∫√(x-4x∧2)dx ∫4/((2-6X-X^2)^(5/2)) dx 计算不定积分∫dx/(4x^2+4x+5) ∫dx／4x^2+4x+5