(a+2)^2+(b+3)^2=0,求axb

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(a+2)^2+(b+3)^2=0,求axb(a+2)^2+(b+3)^2=0,求axb(a+2)^2+(b+3)^2=0,求axba=-2;b=-3;所以a*b=6

(a+2)^2+(b+3)^2=0,求axb
(a+2)^2+(b+3)^2=0,求axb

(a+2)^2+(b+3)^2=0,求axb
a=-2;b=-3;所以a*b=6