方程(1+√2)x²-(1-√2)x=0解是?

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方程(1+√2)x²-(1-√2)x=0解是?方程(1+√2)x²-(1-√2)x=0解是?方程(1+√2)x²-(1-√2)x=0解是?(1+√2)x²-(1

方程(1+√2)x²-(1-√2)x=0解是?
方程(1+√2)x²-(1-√2)x=0解是?

方程(1+√2)x²-(1-√2)x=0解是?
(1+√2)x²-(1-√2)x=0
x[(1+√2)x-(1-√2)]=0
X=0或者x=(1-√2)/(1+√2)=(1-√2)(√2-1)/(1+√2)(√2-1)=2√2-3

(1+√2)x²-(1-√2)x=0
(1+√2)x²=(1-√2)x
x²=x
x=0 x=1