lim趨近無窮x²7x開根號

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(lim) x/(x-y)

(lim)x/(x-y)(lim)x/(x-y)(lim)x/(x-y)令y=kx,则x/(x-y)=x/[(1-k)x]=1/(1-k).lim_{x->0}{x/[(1-k)x]}=1/(1-k)

lim x→

limx→limx→limx→limx→1=limx→1=limx→1=limx→1=1/(√4+2)=1/(2+2)=1/4

lim(x(sin)^2)

lim(x(sin)^2)lim(x(sin)^2)lim(x(sin)^2)x趋于多少?

lim xlnx (x->+0)

limxlnx(x->+0)limxlnx(x->+0)limxlnx(x->+0)lim(x→0+)xlnx=lim(x→0+)lnx/(1/x)=lim(x→0+)(1/x)/(-1/x^2)=l

(lim) x/x-y=

(lim)x/x-y=(lim)x/x-y=(lim)x/x-y=你这个题目存在很多问题,(lim)x/x-y是X除以X在减去Y呢,还是除以(X-Y)这个整体啊,细节问题啊,值得注意.如果我猜的没错的

lim(x)lim(x→∞) [(x-1)/(x+1)]^2x 为什么 lim(x->∞) {[(-

lim(x)lim(x→∞)[(x-1)/(x+1)]^2x为什么lim(x->∞){[(-2)/(x+1)]*2x}=-4lim(x)lim(x→∞)[(x-1)/(x+1)]^2x为什么lim(x

(1)lim[(x+1)(x-2)]/[(x-1)(3x-1)]=1/2(2)lim(2x+7)/[

(1)lim[(x+1)(x-2)]/[(x-1)(3x-1)]=1/2(2)lim(2x+7)/[(x-1)(x+2)]=0(3)lim(3x^2+2x+1)/[(3x+1)(3x-1)]=1/3(

1.lim (1-7x)^(4/x) (x趋近0)2.lim (4x-3)/ln(3+5e^x) (

1.lim(1-7x)^(4/x)(x趋近0)2.lim(4x-3)/ln(3+5e^x)(x趋近正无穷)1.lim(1-7x)^(4/x)(x趋近0)2.lim(4x-3)/ln(3+5e^x)(x

lim(x-3/x+1)^x lim趋向无穷大

lim(x-3/x+1)^xlim趋向无穷大lim(x-3/x+1)^xlim趋向无穷大lim(x-3/x+1)^xlim趋向无穷大关键:分类讨论||x-1|-3|+|3x+1|当x≥4,则:x-4+

lim(x→0)ln tan7x/ln tan2x= lim(x->0) [7(tan2x)·cos

lim(x→0)lntan7x/lntan2x=lim(x->0)[7(tan2x)·cos²2x]/[2(tan7x)·cos²7x]这个步骤是怎么转换的,lim(x→0)lnt

lim x—0 (tan2x)/7x详细过程

limx—0(tan2x)/7x详细过程limx—0(tan2x)/7x详细过程limx—0(tan2x)/7x详细过程因为当x->0时tanx与x是等价无穷小,所以limx—0(tan2x)/7x=

lim 7*sinx/x=?(x->0)

lim7*sinx/x=?(x->0)lim7*sinx/x=?(x->0)lim7*sinx/x=?(x->0)0/0的形式.用罗必达法则.7limcosx=>7*cos(0)=77。。。。

一道数学题lim f(X)=3 (X---1-)and lim f(x)=7 (x---1+)问li

一道数学题limf(X)=3(X---1-)andlimf(x)=7(x---1+)问limx----1f(x)是否存在?一道数学题limf(X)=3(X---1-)andlimf(x)=7(x---

lim(X->0)(7x^6+2x-1)/(2x^6+x+3)=?

lim(X->0)(7x^6+2x-1)/(2x^6+x+3)=?lim(X->0)(7x^6+2x-1)/(2x^6+x+3)=?lim(X->0)(7x^6+2x-1)/(2x^6+x+3)=?-

lim(x→∞)(7x^3+4x)/(2x^3-x^2+3)=?

lim(x→∞)(7x^3+4x)/(2x^3-x^2+3)=?lim(x→∞)(7x^3+4x)/(2x^3-x^2+3)=?lim(x→∞)(7x^3+4x)/(2x^3-x^2+3)=?7/2都

lim (x->0) 3x/(sinx-x)

lim(x->0)3x/(sinx-x)lim(x->0)3x/(sinx-x)lim(x->0)3x/(sinx-x)无穷大.sinx和x是同一阶的,于是lim(sinx/x)=1.

lim((x+sinx)/(x-cosx))x->无穷

lim((x+sinx)/(x-cosx))x->无穷lim((x+sinx)/(x-cosx))x->无穷lim((x+sinx)/(x-cosx))x->无穷lim((x+sinx)/(x-cos

lim(x-cosx)/x x→-∞

lim(x-cosx)/xx→-∞lim(x-cosx)/xx→-∞lim(x-cosx)/xx→-∞x→-∞lim(x-cosx)/x=lim1-cosx/x=lim1-limcosx/x=1-li

lim (x→0)x-sinx/x

lim(x→0)x-sinx/xlim(x→0)x-sinx/xlim(x→0)x-sinx/x原式=0-1=-1lim(x→0)sinx/x=sinc(0)=0因为:在0附近,sinx=x-x^3/

lim[(x-1)/(x+1)]^x

lim[(x-1)/(x+1)]^xlim[(x-1)/(x+1)]^xlim[(x-1)/(x+1)]^x罗毕达法则求导0