lg5*lg20+(lg2)^
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lg5*lg20+(lg2)^lg5*lg20+(lg2)^lg5*lg20+(lg2)^lG(5)*LG(20)+(LG(2))^2=LG(5)*(LG(4)+LG(5))+(LG(2))^2=(l
lg5*lg20+(lg2)^
lg5*lg20+(lg2)^
lg5*lg20+(lg2)^
lG(5)*LG(20)+(LG(2))^2
=LG(5)*(LG(4)+LG(5))+(LG(2))^2
=(lG(5))^2+2LG(5)*LG(2)+(LG(2))^2
=(LG(5)+LG(2))^2
=(LG(10))^2=1
lg5*lg20+(lg2)^
(lg2)^2+lg5*lg20
(lg2)^2+lg20*lg5
lg2*lg2+lg20*lg5=?
lg2*lg50+lg5*lg20-2lg5*lg2
lg5·lg20+(lg2)^2
lg2*lg50-lg5*lg20-lg4
为什么lg5*lg20=lg5*(1+lg2)
lg5^2+lg4+lg5*lg20+(lg2)^@
lg5^2+lg4+lg5*lg20+(lg2)^2
lg2lg50+lg5×lg20-lg100×lg5×lg2=
(lg2)^2+lg20*lg5+(lg5)^2
（lg2)*(lg2)+lg5*lg20-1怎么计算
问道对数题 lg2*lg50+lg20*lg5-2lg5*lg2
求值lg2*lg50+lg5*lg20-lg100*lg2*lg5
（lg2)^2+lg5·lg20-1=?
（lg2）的平方+lg20×lg5答案,
(lg2)^2 lg5×lg20－1