若x/(x^2-ax+1)=1,求x/(x^4-a^2x^2+1)

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若x/(x^2-ax+1)=1,求x/(x^4-a^2x^2+1)若x/(x^2-ax+1)=1,求x/(x^4-a^2x^2+1)若x/(x^2-ax+1)=1,求x/(x^4-a^2x^2+1)x

若x/(x^2-ax+1)=1,求x/(x^4-a^2x^2+1)
若x/(x^2-ax+1)=1,求x/(x^4-a^2x^2+1)

若x/(x^2-ax+1)=1,求x/(x^4-a^2x^2+1)
x=x^2-ax+1,x^2-(a+1)x+1=0,令[-(a+1)]^2-4×1×1=0,所以a=1或-3,所以x/(x^2-x+1)=1,x=1,或x/(x^2+3x+1)=1,x=-1,即当a=1时x=1,当a=-3时,x=-1,所以x/(x^4-a^2x^2+1)=1或1/7.