cosx*cosy=1,sin(x+y)=?

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cosx*cosy=1,sin(x+y)=?cosx*cosy=1,sin(x+y)=?cosx*cosy=1,sin(x+y)=?cos在[-1,1]相乘是1则两个都等于-1或都等于1所以此时sin

cosx*cosy=1,sin(x+y)=?
cosx*cosy=1,sin(x+y)=?

cosx*cosy=1,sin(x+y)=?
cos在[-1,1]
相乘是1则两个都等于-1或都等于1
所以此时sinx=0,siny=0
所以原式=sinxcosy+cosxsiny=0

1

cos在[-1,1]
相乘是1则两个都等于-1或都等于1
所以此时sinx=0,siny=0
所以原式=sinxcosy+cosxsiny=0

cosx*cosy=1
cosx=1,cosy=1
sinx=0,siny=0
sin(x+y)
=sinxcosy+cosxsiny
=0+0
=0

cosx*cosy=1
cosx=-1,cosy=-1
sinx=0,siny=0
sin(x+y)
=sinxcosy+cosxsiny
=0+0
=0