化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)=

来源:学生作业帮助网 编辑:六六作业网 时间:2024/05/14 14:09:33
化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)=化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)=化简:sin(2π-α)co

化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)=
化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)=

化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)=
sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)
=(-sinα)*(-sinα)+(-cosα)*(-cosα)
=(sinα)^2+(cosα)^2=1