已知cos(5л/12+α)=1/3,且-л

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已知cos(5л/12+α)=1/3,且-л已知cos(5л/12+α)=1/3,且-л已知cos(5л/12+α)=1/3,且-л∵cos(л/12-α)=cos(π/2-(5л/12+α))=si

已知cos(5л/12+α)=1/3,且-л
已知cos(5л/12+α)=1/3,且-л<α<-л/2,则cos(л/12-α)等于

已知cos(5л/12+α)=1/3,且-л
∵cos(л/12-α)
=cos(π/2-(5л/12+α))
=sin(5л/12+α)
∵-л<α<-л/2
∴-π/2<5л/12+α<-π/12
∵cos(5л/12+α)=1/3
∴sin(5л/12+α)=-2√2/3
∴cos(л/12-α)=-2√2/3