3x-2y=0,求3xy-y方除以x方-2xy

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3x-2y=0,求3xy-y方除以x方-2xy3x-2y=0,求3xy-y方除以x方-2xy3x-2y=0,求3xy-y方除以x方-2xy3x-2y=03x=2y所以y=2x/3所以原式=(3*2x&

3x-2y=0,求3xy-y方除以x方-2xy
3x-2y=0,求3xy-y方除以x方-2xy

3x-2y=0,求3xy-y方除以x方-2xy
3x-2y=0
3x=2y
所以y=2x/3
所以原式=(3*2x²/3-4x²/9)÷(x²-2*2x²/3)
=(14x²/9)/(-x²/3)
=-14/3

3x=2y
2y²/3x²
=3/2

3xy-y方除以x方-2xy 3x-2y ,y/x=3/2
=(3y/x-y^2/x^2)/(1-2y/x)
=(3*3/2-9/4)/(1-3)
=(9/4)/(-2)
=-9/8

3x-2y=0
3x=2y
3xy-y方除以x方-2xy
=y(3x-y)/x(x-2y)
=y(2y-y)/x(x-3x)
=-y^2/2x^2
=-9/8