x/2=y/3=z/4,则x+2y-z/z=?

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x/2=y/3=z/4,则x+2y-z/z=?x/2=y/3=z/4,则x+2y-z/z=?x/2=y/3=z/4,则x+2y-z/z=?x/2=y/3=z/4=kx=2k,y=3k,z=4kx+2y

x/2=y/3=z/4,则x+2y-z/z=?
x/2=y/3=z/4,则x+2y-z/z=?

x/2=y/3=z/4,则x+2y-z/z=?
x/2=y/3=z/4=k
x=2k,y=3k,z=4kx+2y-z/z=(2k+6k-4k)/(4k)=1

x/2=y/3=z/4
所以y=3x/2
z=2x
所以原式=(x+3x-2x)/2x
=2x/2x
=1

设x/2=y/3=z/4=k
∴x=2k,y=3k,z=4k
∴(x+2y-z)/z
=(2k+6k-4k)/4k
=4k/4k
=1