(log5(10))^3-(log5(2))^3-3log5(10)*log2(5)
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(log5(10))^3-(log5(2))^3-3log5(10)*log2(5)(log5(10))^3-(log5(2))^3-3log5(10)*log2(5)(log5(10))^3-(lo
(log5(10))^3-(log5(2))^3-3log5(10)*log2(5)
(log5(10))^3-(log5(2))^3-3log5(10)*log2(5)
(log5(10))^3-(log5(2))^3-3log5(10)*log2(5)
令a=log5(10),b=log5(2)
则a-b=log5(10/2)=log5(5)=1
原式=a^3-b^3-3ab
=(a-b)(a^2+ab+b^2)-3ab
=1*(a^2+ab+b^2)-3ab
=a^2+ab+b^2-3ab
=a^2-2ab+b^2
=(a-b)^2
=1^2
=1
1-3log2（10）
计算（2lg5^2+log5^3)/(log5^10+0.5log5^0.36+1/3log5^8)
(log5(10))^3-(log5(2))^3-3log5(10)*log2(5)
log5 2+log5 3+log5 1/6=?
2log5^10+log5^0.25=?
计算2log5^10+log5^0.25=
2log5 10+log5 0.25=?
2log5 10+log5 0.25等于多少?
2log5 10+log5 0.25 怎样计算,
(log5 3)2 为什么>log5 3
[log5(2)*log7(9)]/[log5(3)*log7(4)] [log5(2)*log7(9)]/[log5(3)*log7(4)]
log5【35】-2log5[7/3】+log5【7】-log5【1.8】 化简
log5（35）-2log5（7/3）+log5（7）-log5（1.8）
log5·log5(3)·log5(1/3)log3(5)·log5(3)·log5(1/3)log3(2)·log5(3)·log8(5)不好意思
8^(-1/3)+log3(1/27)+log6(5)*[log5(2)+log5(3)]+10^lg3=?
2log5（10）+log5（0.25)=?急用
计算：2log5 10+log5 0.25=______
求解2(log5)10+(log5)0.25麻烦啦
计算题.2log5 10+log5 0.25(5是底数)