【分式的加减】几道计算题(带过程)(1)(1 / x)-( 1 / x+1)=(2)(x / x-2)- (8 / x ² -4)=(3)(x / x+1)- (1 / x-1)- (2 / x ² -1)=(4)(1/x+1/y)² -(1/x-1/y)² =(5)(x-1 /

来源:学生作业帮助网 编辑:六六作业网 时间:2024/05/11 00:18:44
【分式的加减】几道计算题(带过程)(1)(1/x)-(1/x+1)=(2)(x/x-2)-(8/x²-4)=(3)(x/x+1)-(1/x-1)-(2/x²-1)=(4)(1/x+

【分式的加减】几道计算题(带过程)(1)(1 / x)-( 1 / x+1)=(2)(x / x-2)- (8 / x ² -4)=(3)(x / x+1)- (1 / x-1)- (2 / x ² -1)=(4)(1/x+1/y)² -(1/x-1/y)² =(5)(x-1 /
【分式的加减】几道计算题(带过程)
(1)(1 / x)-( 1 / x+1)=
(2)(x / x-2)- (8 / x ² -4)=
(3)(x / x+1)- (1 / x-1)- (2 / x ² -1)=
(4)(1/x+1/y)² -(1/x-1/y)² =
(5)(x-1 / x ² -3x+2)- (x+2 / x ² +3x+2)=
(6)【(x ² -4 / x ² -x-6 )- (x +2 / x-3)】÷ (4/x-3)=

【分式的加减】几道计算题(带过程)(1)(1 / x)-( 1 / x+1)=(2)(x / x-2)- (8 / x ² -4)=(3)(x / x+1)- (1 / x-1)- (2 / x ² -1)=(4)(1/x+1/y)² -(1/x-1/y)² =(5)(x-1 /
(1)(1 / x)-( 1 / x+1)=[(x+1)-x]/(x+1)x=x/(x²+x)
(2)(x / x-2)- (8 / x ² -4)=[x(x+2)-8]/(x ² -4)=[(x-2)(x+4)]/[(x-2)(x+2)]=(x+4)/(x+2)
(3)(x / x+1)- (1 / x-1)- (2 / x ² -1)=[x(x-1)-(x+1)-2]/(x ² -1)=(x ²-2x-3)/[(x-1)(x+1)]=[(x-3)(x+1)]/[(x-1)(x+1)]=(x-3)(x-1)
(4)(1/x+1/y)² -(1/x-1/y)² =[(1/x+1/y) -(1/x-1/y)][(1/x+1/y)+(1/x-1/y)]=4/xy
(5)(x-1 / x ² -3x+2)- (x+2 / x ² +3x+2)=(x-1)/(x-1)(x-2)-(x+2)/(x+1)(x+2)=1/(x-2)-1/(x+1)=[(x+1)-(x-2)]/(x-2)(x+1)=3/(x ²-x-2)
(6)【(x ² -4 / x ² -x-6 )- (x +2 / x-3)】÷ (4/x-3)=(x-2)(x+2)/(x+2)(x-3)-(x+2)/(x-3)=(x-2)/(x-3)-(x+2)/(x-3)=[(x-2)-(x+2)]/(x-3)=4/(3-x)

(1)(1/x)-(1/x+1)
=(x+1-x)/x(x+1)
=1/(x^2+x)
(2)(x/x-2)-(8/x^2 -4)
=x(x+2)/(x^2-4)-8/(x^2)-4
=(x^2+2x-8)/(x^2-4)
=(x+4)(x-2)/(x+2)(x-2)
=(x+4)/(x+2)
(3)(x/x+1)-(1/x-1)-(...

全部展开

(1)(1/x)-(1/x+1)
=(x+1-x)/x(x+1)
=1/(x^2+x)
(2)(x/x-2)-(8/x^2 -4)
=x(x+2)/(x^2-4)-8/(x^2)-4
=(x^2+2x-8)/(x^2-4)
=(x+4)(x-2)/(x+2)(x-2)
=(x+4)/(x+2)
(3)(x/x+1)-(1/x-1)-(2/x^-1)
=[x(x-1)-(x+1)-2]/(x^2-1)
=(x^2-2x-3)/[(x-1)(x+1)]
=[(x-3)(x+1)]/[(x-1)(x+1)]
=(x-3)(x-1)
(4)(1/x+1/y)^2-(1/x-1/y)^2
=[(1/x+1/y)-(1/x-1/y)][(1/x+1/y)+(1/x-1/y)]
=4/xy
(5)(x-1/x^2-3x+2)-(x+2/x^2+3x+2)
=(x-1)/(x-1)(x-2)-(x+2)/(x+1)(x+2)
=1/(x-2)-1/(x+1)
=[(x+1)-(x-2)]/(x-2)(x+1)
=3/(x^2-x-2)
(6)[(x^2-4/x^2-x-6)-(x+2/x-3)]÷(4/x-3)
=(x-2)(x+2)/(x+2)(x-3)-(x+2)/(x-3)
=(x-2)/(x-3)-(x+2)/(x-3)
=[(x-2)-(x+2)]/(x-3)
=4/(3-x)

收起