已知log3(2)=a,2^b=3,求lga+lgb的值

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已知log3(2)=a,2^b=3,求lga+lgb的值已知log3(2)=a,2^b=3,求lga+lgb的值已知log3(2)=a,2^b=3,求lga+lgb的值log3(2)=a,所以1/lo

已知log3(2)=a,2^b=3,求lga+lgb的值
已知log3(2)=a,2^b=3,求lga+lgb的值

已知log3(2)=a,2^b=3,求lga+lgb的值
log3(2)=a,所以1/log2(3)=a,因为log2(3)=b.所以1/a=b. ab=1 lga+lgb=lgab=lg1=0

log3(2)=a推出3^a=2 ①
2^b=3 ②
将①②得:3^a(^b)=3^(ab)=3推出ab=1
lga+lgb=lgab=lg(1)=0