log(2)1/25乘以log(3)1/8乘以log(5)1/9
来源：学生作业帮助网 编辑：六六作业网 时间：2024/05/18 08:29:24
log(2)1/25乘以log(3)1/8乘以log(5)1/9log(2)1/25乘以log(3)1/8乘以log(5)1/9log(2)1/25乘以log(3)1/8乘以log(5)1/9log(
log(2)1/25乘以log(3)1/8乘以log(5)1/9
log(2)1/25乘以log(3)1/8乘以log(5)1/9
log(2)1/25乘以log(3)1/8乘以log(5)1/9
log(2)1/25乘以log(3)1/8乘以log(5)1/9
=-2log(2)5*3log(3)2*log(5)3
=-12*ln5/ln2*ln2/ln3*ln3/ln5
=-12
原式=(-2lg5/lg2)×(-3lg2/lg3)×(-2lg3/lg5)
=-12
用换底公式
原式=lg(1/25)/lg(2) * lg(1/8)/lg(3) * lg(1/9)/lg(5)
=[-2lg(5)/lg(2)]*[-3lg(2)/lg(3)]*[-2(3)/lg(5)]
=-2*(-3)*(-2)=-12
log(2)1/25乘以log(3)1/8乘以log(5)1/9
(log(2)9+log(4)1/9)乘以(log(3)2+log(9)0.5) 括号里是底数.计算这道题.
log底数2真数25乘以log底数3真数1/16乘以log底数5真数1/9怎样利用换底公式求下式的值?
2^log(4)(3)加3^log(9)(1/4)加5^log(1/25)(2)
log(2)(25)×log(3)(1/16)×log(5)(1/9)=?
log下标2 3乘以log下标3 4
Log(2)1/25•log(3)1/8•log(5)1/9化简 还有已知log(18)9=a,log(18)5=b求log(36)45 值
2log(5 ) 25+3log(2) 64-8log(2) 1 ( )内代表的是以什么为底
2log(5 ) 25+3log(2) 64-8log(2) 1 ( )内代表的是以什么为底
计算：1/[log(2)3]+1/[log(5)3]=?
log(3)1+log(2)根号2+lg1000
比较log(1/2)0.3,log(3)0.2的大小
计算：8^(1-log(83))(27^(2/3))-log(32)
log(根号2-1)(3
log(10)(25/9)减log(10)(7/4)减log(10)(1/9)加1/2log(10)(49)
求值 log【9(下标)】3+log【 9（下标）】27 log【2】（1/2）- log【1/2】2
log(1/2)3,log(1/3)3,log(1/4)3比大小
64^1/3-(-2/3)^0+log(2)8+(log(8)9)/(log(2)3)