当x→0时,1-cosx与axsinx是等价无穷小,则a=

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当x→0时,1-cosx与axsinx是等价无穷小,则a=当x→0时,1-cosx与axsinx是等价无穷小,则a=当x→0时,1-cosx与axsinx是等价无穷小,则a=1=lim(x→0)(1-

当x→0时,1-cosx与axsinx是等价无穷小,则a=
当x→0时,1-cosx与axsinx是等价无穷小,则a=

当x→0时,1-cosx与axsinx是等价无穷小,则a=
1=lim(x→0)(1-cosx)/(axsinx)
=lim(x→0)(x^2/2)/(ax^2)=1/(2a)
所以:a=1/2