x2+y2+2xy=256 x2+y2-2xy=4 (x2,
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x2+y2+2xy=256x2+y2-2xy=4(x2,x2+y2+2xy=256x2+y2-2xy=4(x2,x2+y2+2xy=256x2+y2-2xy=4(x2,x2+y2+2xy=256(x+
x2+y2+2xy=256 x2+y2-2xy=4 (x2,
x2+y2+2xy=256 x2+y2-2xy=4 (x2,
x2+y2+2xy=256 x2+y2-2xy=4 (x2,
x2+y2+2xy=256 (x+y)=256 x+y=±16 x2+y2-2xy=4 (x-y)=4 x-y=±2 你问怎么做,我不太理解你的意思,是求x、y的值,还是什么? 谢谢采纳,如不懂,请追问
麻烦采纳,谢谢!
(x2-2xy+y2)-(x2+2xy+y2)=什么
x2+y2+2xy=256 x2+y2-2xy=4 (x2,
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