log2(1+根号2+根号3）+log2（1+根号2-根号3）=
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log2(1+根号2+根号3）+log2（1+根号2-根号3）=log2(1+根号2+根号3）+log2（1+根号2-根号3）=log2(1+根号2+根号3）+log2（1+根号2-根号3）=log2
log2(1+根号2+根号3）+log2（1+根号2-根号3）=
log2(1+根号2+根号3）+log2（1+根号2-根号3）=
log2(1+根号2+根号3）+log2（1+根号2-根号3）=
log2(1+根号2+根号3）+log2（1+根号2-根号3）
=log2[(1+√2+√3)(1+√2-√3)]
=log2[(1+√2)²-(√3)²]
=log2[2√2]
=log2[2^(3/2)]
=3/2
祝愉快!
log2(1+根号2+根号3）+log2（1+根号2-根号3）=
log2(1+根号2+根号3)+log2(1+根号2 -根号3）
log2+根号3（2-根号3）
根号下[(log2^3)^2-4log2^3+4]+log2^(1/3)
化简根号下[(log2^3)^2-4log2^3+4]+log2^(1/3)
log2(1+根号2+根号3）+log2（1+根号2-根号3）=中有一步是怎样来的解：log2(1+根号2+根号3）+log2（1+根号2-根号3）=log2[(1+√2+√3)(1+√2-√3)]=log2[(1+√2)²-(√3)²]=log2[2√2]=log2[2^(3/2)]=3/2这里log2[2
log2-根号3(2+根号3)
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log2 根号2怎么计算?
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